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Discussion :: Time and Work

  1. A and B can do a job together in 7 days. A is 1\(\frac {3 } { 4 } \)times as efficient as B. The same job can be done by A alone in :

  2. A.

    9\( \frac { 1 } {3 } \)days

    B.

    11 days

    C.

    12\(\frac { 1 } { 4 } \)days

    D.

    16\( \frac { 1 } {3 } \)days

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    Answer : Option B

    Explanation :

    (A's 1 day's work) : (B's 1 day's work) =\(\frac { 7 } {4 } \):1=7:4

     

    Let A's and B's 1 day's work be 7x and 4x respectively.

     

    Then, 7x + 4x =\( \frac { 1 } {7 } \)     11x =\( \frac { 1 } {7 } \)     x =\( \frac { 1 } {7 7} \)

     

    Therefore A's 1 day's work =[\( \frac { 1 } {7 7} *7]\)=\( \frac { 1 } {11} \)

     


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