Discussion :: Time and Work
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If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
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Answer : Option A
Explanation :
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y =\( \frac { 1 } { 10 } \)and 26x + 48y =\( \frac { 1 } { 2 } \)
Solving these two equations, we get : x =\( \frac { 1 } { 100 } \)and y =\( \frac { 1 } { 200 } \)
(15 men + 20 boy)'s 1 day's work =[\( \frac { 15 } { 100 } \)+\( \frac { 20 } { 200 } \)]=\( \frac { 1 } { 4} \)
15 men and 20 boys can do the work in 4 days.
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